And the subheading should suggest what's coming...
Can we find a base in which 21 can be divided by 12 without remainder? And why should we? - Because someone said it couldn't be done. They may well have meant that it can't be done if the base is a positive number - and in fact, if you use base (-5) then 21 = 3 x 12 is true.
Which led me to look at some other results in other bases - not recent discoveries, I might add; the keyboard is ready and willing to work, but occasional bursts of lethargy often hit the typist, in particular Nap Attacks as favoured by Garfield.1
31 = 2 x 13 (base 5)
41 = 3 x 14 (base eleven)
51 = 3 x 15 (base seven)
51 = 4 x 15 (base nineteen)
In tabular form:
Number | Bases |
31 | 5 |
41 | 11 |
51 | 7, 19 |
61 | 29 |
71 | 9, 17, 41 |
81 | 13, 55 |
91 | 11, 31, 71 |
T1 | 23, 89 |
E1 | 13, 19, 29, 49 |
and here are some with 2 as unit-figure | |
---|---|
52 | 8 |
72 | 19 |
82 | 11 |
92 | 34 |
T2 | 19 |
E2 | 14, 53 |